What are the solutions to the equation d^3-1=0 ?

The solutions to the equation d^3-1=0 are d=1,d=-1/2+(sqrt(3))/2 i,d=-1/2-(sqrt(3))/2 i

Find the zeros of d^3-1=0

The zeros of d^3-1=0 are d=1,d=-1/2+(sqrt(3))/2 i,d=-1/2-(sqrt(3))/2 i

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d^{3} - 1 = 0

d = 1, d = - \frac{1}{2} + \frac{3}{2} i, d = - \frac{1}{2} - \frac{3}{2} i

Solution steps

d^{3} - 1 = 0

Move

1

to the right side

d^{3} = 1

For

x^{3} = f (a)

the solutions are

d = 1, d = \frac{- 1 + 3 i}{2}, d = \frac{- 1 - 3 i}{2}

Simplify

\frac{- 1 + 3 i}{2} : - \frac{1}{2} + \frac{3}{2} i

Simplify

\frac{- 1 - 3 i}{2} : - \frac{1}{2} - \frac{3}{2} i

d = 1, d = - \frac{1}{2} + \frac{3}{2} i, d = - \frac{1}{2} - \frac{3}{2} i

6 x^{4} + 29 x^{2} + 28 = 0

x^{2} (x^{4} - 9) = 8 x^{4}

7 (z^{2} - 3 z - 4) (z + 7) = 0

45 z^{3} + 18 z^{2} - 5 z - 2 = 0

- x^{3} - 2 x^{2} - 4 x - 8 = 0

What are the solutions to the equation d^3-1=0 ?
The solutions to the equation d^3-1=0 are d=1,d=-1/2+(sqrt(3))/2 i,d=-1/2-(sqrt(3))/2 i
Find the zeros of d^3-1=0
The zeros of d^3-1=0 are d=1,d=-1/2+(sqrt(3))/2 i,d=-1/2-(sqrt(3))/2 i