What are the solutions to the equation -x^3-2x^2-4x-8=0 ?

The solutions to the equation -x^3-2x^2-4x-8=0 are x=-2,x=2i,x=-2i

Find the zeros of -x^3-2x^2-4x-8=0

The zeros of -x^3-2x^2-4x-8=0 are x=-2,x=2i,x=-2i

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- x^{3} - 2 x^{2} - 4 x - 8 = 0

x = - 2, x = 2 i, x = - 2 i

Solution steps

- x^{3} - 2 x^{2} - 4 x - 8 = 0

Factor

- x^{3} - 2 x^{2} - 4 x - 8 : - (x + 2) (x^{2} + 4)

- (x + 2) (x^{2} + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x^{2} + 4 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x^{2} + 4 = 0 : x = 2 i, x = - 2 i

The solutions are

x = - 2, x = 2 i, x = - 2 i

5 x^{4} + 3 x^{2} = 0

9 x^{6} + 6 x^{4} - 10000 = 0

(x^{2} - 5) (x - 2) = 0

12 x^{3} + 27 x^{2} - 30 x = 0

(1 - x^{2})^{2} = 0

What are the solutions to the equation -x^3-2x^2-4x-8=0 ?
The solutions to the equation -x^3-2x^2-4x-8=0 are x=-2,x=2i,x=-2i
Find the zeros of -x^3-2x^2-4x-8=0
The zeros of -x^3-2x^2-4x-8=0 are x=-2,x=2i,x=-2i