What are the solutions to the equation y^3+4y^2-4y-16=0 ?

The solutions to the equation y^3+4y^2-4y-16=0 are y=-4,y=-2,y=2

Find the zeros of y^3+4y^2-4y-16=0

The zeros of y^3+4y^2-4y-16=0 are y=-4,y=-2,y=2

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y^{3} + 4 y^{2} - 4 y - 16 = 0

y = - 4, y = - 2, y = 2

Solution steps

y^{3} + 4 y^{2} - 4 y - 16 = 0

Factor

y^{3} + 4 y^{2} - 4 y - 16 : (y + 4) (y + 2) (y - 2)

(y + 4) (y + 2) (y - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y + 4 = 0 or y + 2 = 0 or y - 2 = 0

Solve

y + 4 = 0 : y = - 4

Solve

y + 2 = 0 : y = - 2

Solve

y - 2 = 0 : y = 2

The solutions are

y = - 4, y = - 2, y = 2

(3) = 5 x^{3} - 18

3 x^{3} + 6 x^{2} = 9 x

5^{2} = 5 x^{5}

x, y + 1 = x^{3}

w w^{2} - 6 w - 7 = 0

What are the solutions to the equation y^3+4y^2-4y-16=0 ?
The solutions to the equation y^3+4y^2-4y-16=0 are y=-4,y=-2,y=2
Find the zeros of y^3+4y^2-4y-16=0
The zeros of y^3+4y^2-4y-16=0 are y=-4,y=-2,y=2