What are the solutions to the equation 2x^4=128 ?

The solutions to the equation 2x^4=128 are x=2sqrt(2),x=-2sqrt(2),x=2sqrt(2)i,x=-2sqrt(2)i

Find the zeros of 2x^4=128

The zeros of 2x^4=128 are x=2sqrt(2),x=-2sqrt(2),x=2sqrt(2)i,x=-2sqrt(2)i

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2 x^{4} = 128

x = 22, x = - 22, x = 22 i, x = - 22 i

Solution steps

2 x^{4} = 128

Divide both sides by

2

x^{4} = 64

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

u^{2} = 64

Solve

u^{2} = 64 : u = 64, u = - 64

u = 64, u = - 64

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = 64 : x = 22, x = - 22

Solve

x^{2} = - 64 : x = 22 i, x = - 22 i

The solutions are

x = 22, x = - 22, x = 22 i, x = - 22 i

333 = 80 \cdot (1 + x)^{7}

- a^{3} + 24 a^{2} - 180 a + 432 = 0

x^{4} = 6 x^{2}

(9 x - 4) x^{7} = 7 x (9 x - 4)

x^{9} = 1 0^{63}

What are the solutions to the equation 2x^4=128 ?
The solutions to the equation 2x^4=128 are x=2sqrt(2),x=-2sqrt(2),x=2sqrt(2)i,x=-2sqrt(2)i
Find the zeros of 2x^4=128
The zeros of 2x^4=128 are x=2sqrt(2),x=-2sqrt(2),x=2sqrt(2)i,x=-2sqrt(2)i