What are the solutions to the equation x^3+3x^2+18x=0 ?

The solutions to the equation x^3+3x^2+18x=0 are x=0,x=-3/2+i(3sqrt(7))/2 ,x=-3/2-i(3sqrt(7))/2

Find the zeros of x^3+3x^2+18x=0

The zeros of x^3+3x^2+18x=0 are x=0,x=-3/2+i(3sqrt(7))/2 ,x=-3/2-i(3sqrt(7))/2

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x^{3} + 3 x^{2} + 18 x = 0

x = 0, x = - \frac{3}{2} + i \frac{3 7}{2}, x = - \frac{3}{2} - i \frac{3 7}{2}

Solution steps

x^{3} + 3 x^{2} + 18 x = 0

Factor

x^{3} + 3 x^{2} + 18 x : x (x^{2} + 3 x + 18)

x (x^{2} + 3 x + 18) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x^{2} + 3 x + 18 = 0

Solve

x^{2} + 3 x + 18 = 0 : x = - \frac{3}{2} + i \frac{3 7}{2}, x = - \frac{3}{2} - i \frac{3 7}{2}

The solutions are

x = 0, x = - \frac{3}{2} + i \frac{3 7}{2}, x = - \frac{3}{2} - i \frac{3 7}{2}

625 = x^{4}

x^{5} + 2 x^{3} + x^{2} + 2 = 0

- x^{3} - 5 x^{2} + 25 x + 125 = 0

2 x^{3} - 2 x^{2} - 1 = 0

x^{4} + 149 x^{2} + 4900 = 0

What are the solutions to the equation x^3+3x^2+18x=0 ?
The solutions to the equation x^3+3x^2+18x=0 are x=0,x=-3/2+i(3sqrt(7))/2 ,x=-3/2-i(3sqrt(7))/2
Find the zeros of x^3+3x^2+18x=0
The zeros of x^3+3x^2+18x=0 are x=0,x=-3/2+i(3sqrt(7))/2 ,x=-3/2-i(3sqrt(7))/2