What are the solutions to the equation (12+x)/2 =(x^2+36)^2 ?

The solutions to the equation (12+x)/2 =(x^2+36)^2 are No Solution for x\in\mathbb{R}

Find the zeros of (12+x)/2 =(x^2+36)^2

The zeros of (12+x)/2 =(x^2+36)^2 are No Solution for x\in\mathbb{R}

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\frac{12 + x}{2} = (x^{2} + 36)^{2}

No Solution for x \in R

Solution steps

\frac{12 + x}{2} = (x^{2} + 36)^{2}

Multiply both sides by

2

12 + x = 2 (x^{2} + 36)^{2}

Expand

2 (x^{2} + 36)^{2} : 2 x^{4} + 144 x^{2} + 2592

12 + x = 2 x^{4} + 144 x^{2} + 2592

Switch sides

2 x^{4} + 144 x^{2} + 2592 = 12 + x

Move

x

to the left side

2 x^{4} + 144 x^{2} + 2592 - x = 12

Move

12

to the left side

2 x^{4} + 144 x^{2} - x + 2580 = 0

Find one solution for

2 x^{4} + 144 x^{2} - x + 2580 = 0

using Newton-Raphson:

No Solution for

x \in R

The solution is

No Solution for x \in R

2 x^{3} + x^{2} - 18 x - 9 = 0

r, S = 30 - r^{30}

(x^{2} - 3 x) (2 x + 3) (x - 1) = 0

2 x^{4} - x^{2} - 3 = 0

z^{4} = 121

What are the solutions to the equation (12+x)/2 =(x^2+36)^2 ?
The solutions to the equation (12+x)/2 =(x^2+36)^2 are No Solution for x\in\mathbb{R}
Find the zeros of (12+x)/2 =(x^2+36)^2
The zeros of (12+x)/2 =(x^2+36)^2 are No Solution for x\in\mathbb{R}