What are the solutions to the equation 7x^5=35-29 ?

The solutions to the equation 7x^5=35-29 are x=\sqrt[5]{6/7}

Find the zeros of 7x^5=35-29

The zeros of 7x^5=35-29 are x=\sqrt[5]{6/7}

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7 x^{5} = 35 - 29

Decimal Notation

x = 0.96964 \dots

Solution steps

7 x^{5} = 35 - 29

Subtract the numbers:

35 - 29 = 6

7 x^{5} = 6

Divide both sides by

7

x^{5} = \frac{6}{7}

For

x^{n} = f (a)

, n is odd, the solution is

r^{3} - 3 r^{2} + 6 r - 6 = 0

s^{3} + 6 s^{2} + 11 s + 6 = 0

(4 + 3 x) \cdot x^{5} = (4 + 3 x)^{5}

4.328 = 541 (1 + \frac{y}{4})^{15}

x^{4} - 5 x^{3} + x^{2} - 2 x - 15 = 0

What are the solutions to the equation 7x^5=35-29 ?
The solutions to the equation 7x^5=35-29 are x=\sqrt[5]{6/7}
Find the zeros of 7x^5=35-29
The zeros of 7x^5=35-29 are x=\sqrt[5]{6/7}