What are the solutions to the equation -x^3+9x^2-27x+27=0 ?

The solutions to the equation -x^3+9x^2-27x+27=0 are x=3

Find the zeros of -x^3+9x^2-27x+27=0

The zeros of -x^3+9x^2-27x+27=0 are x=3

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- x^{3} + 9 x^{2} - 27 x + 27 = 0

x = 3

Solution steps

- x^{3} + 9 x^{2} - 27 x + 27 = 0

Factor

- x^{3} + 9 x^{2} - 27 x + 27 : - (x - 3)^{3}

- (x - 3)^{3} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0

Solve

x - 3 = 0 : x = 3

The solution is

x = 3

3 (x^{3} + 8) (x + 5) = 0

x^{3} - 4 x - x + 4 = 0

p^{4} - 13 p^{2} + 36 = 0

27 d^{4} = 18 d^{2}

x^{3} + 4 x^{2} - 6 = 0

What are the solutions to the equation -x^3+9x^2-27x+27=0 ?
The solutions to the equation -x^3+9x^2-27x+27=0 are x=3
Find the zeros of -x^3+9x^2-27x+27=0
The zeros of -x^3+9x^2-27x+27=0 are x=3