What are the solutions to the equation x^3-4x^2-13x+52=0 ?

The solutions to the equation x^3-4x^2-13x+52=0 are x=4,x=-sqrt(13),x=sqrt(13)

Find the zeros of x^3-4x^2-13x+52=0

The zeros of x^3-4x^2-13x+52=0 are x=4,x=-sqrt(13),x=sqrt(13)

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x^{3} - 4 x^{2} - 13 x + 52 = 0

x = 4, x = - 13, x = 13

Decimal Notation

x = 4, x = - 3.60555 \dots, x = 3.60555 \dots

Solution steps

x^{3} - 4 x^{2} - 13 x + 52 = 0

Factor

x^{3} - 4 x^{2} - 13 x + 52 : (x - 4) (x + 13) (x - 13)

(x - 4) (x + 13) (x - 13) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 4 = 0 or x + 13 = 0 or x - 13 = 0

Solve

x - 4 = 0 : x = 4

Solve

x + 13 = 0 : x = - 13

Solve

x - 13 = 0 : x = 13

The solutions are

x = 4, x = - 13, x = 13

- x (x - 9) (4 x + 9) = 0

a^{4} - 2 a^{2} + 1 = 0

a \cdot a^{5} = a

r^{3} = \frac{3}{9}

3^{4} - x^{4} = 0

What are the solutions to the equation x^3-4x^2-13x+52=0 ?
The solutions to the equation x^3-4x^2-13x+52=0 are x=4,x=-sqrt(13),x=sqrt(13)
Find the zeros of x^3-4x^2-13x+52=0
The zeros of x^3-4x^2-13x+52=0 are x=4,x=-sqrt(13),x=sqrt(13)