What are the solutions to the equation 2x^4-x^3-14x^2-5x+6=0 ?

The solutions to the equation 2x^4-x^3-14x^2-5x+6=0 are x=-1,x=-2,x= 1/2 ,x=3

Find the zeros of 2x^4-x^3-14x^2-5x+6=0

The zeros of 2x^4-x^3-14x^2-5x+6=0 are x=-1,x=-2,x= 1/2 ,x=3

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2 x^{4} - x^{3} - 14 x^{2} - 5 x + 6 = 0

x = - 1, x = - 2, x = \frac{1}{2}, x = 3

Decimal Notation

x = - 1, x = - 2, x = 0.5, x = 3

Solution steps

2 x^{4} - x^{3} - 14 x^{2} - 5 x + 6 = 0

Factor

2 x^{4} - x^{3} - 14 x^{2} - 5 x + 6 : (x + 1) (x + 2) (2 x - 1) (x - 3)

(x + 1) (x + 2) (2 x - 1) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x + 2 = 0 or 2 x - 1 = 0 or x - 3 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x + 2 = 0 : x = - 2

Solve

2 x - 1 = 0 : x = \frac{1}{2}

Solve

x - 3 = 0 : x = 3

The solutions are

x = - 1, x = - 2, x = \frac{1}{2}, x = 3

- 2 (x + 1)^{3} = 16

t^{3} - 6 t^{2} - 15 t + 40 = 0

x^{4} = 2^{0.5}

2151296 = 400000 (1 + x)^{5}

2 x^{3} - 3 x^{2} + 2 x = - 4 x^{3} + 10 x - 4

What are the solutions to the equation 2x^4-x^3-14x^2-5x+6=0 ?
The solutions to the equation 2x^4-x^3-14x^2-5x+6=0 are x=-1,x=-2,x= 1/2 ,x=3
Find the zeros of 2x^4-x^3-14x^2-5x+6=0
The zeros of 2x^4-x^3-14x^2-5x+6=0 are x=-1,x=-2,x= 1/2 ,x=3