What are the solutions to the equation (x+2)^3=1 ?

The solutions to the equation (x+2)^3=1 are x=-1,x=-5/2+i(sqrt(3))/2 ,x=-5/2-i(sqrt(3))/2

Find the zeros of (x+2)^3=1

The zeros of (x+2)^3=1 are x=-1,x=-5/2+i(sqrt(3))/2 ,x=-5/2-i(sqrt(3))/2

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(x + 2)^{3} = 1

x = - 1, x = - \frac{5}{2} + i \frac{3}{2}, x = - \frac{5}{2} - i \frac{3}{2}

Solution steps

(x + 2)^{3} = 1

For

g^{3} (x) = f (a)

the solutions are

Solve

x + 2 = 1 : x = - 1

Solve

x + 2 = \frac{- 1 + 3 i}{2} : x = - \frac{5}{2} + i \frac{3}{2}

Solve

x + 2 = \frac{- 1 - 3 i}{2} : x = - \frac{5}{2} - i \frac{3}{2}

The solutions are

x = - 1, x = - \frac{5}{2} + i \frac{3}{2}, x = - \frac{5}{2} - i \frac{3}{2}

64 y^{3} - 7 = y - 448 y^{2}

x^{4} - 8 x + 63 = 0

16 x^{4} - 9 = 0

x^{3} - 12 x + 7 = 0

- 2 x (x + 8) (x^{2} - 9) = 0

What are the solutions to the equation (x+2)^3=1 ?
The solutions to the equation (x+2)^3=1 are x=-1,x=-5/2+i(sqrt(3))/2 ,x=-5/2-i(sqrt(3))/2
Find the zeros of (x+2)^3=1
The zeros of (x+2)^3=1 are x=-1,x=-5/2+i(sqrt(3))/2 ,x=-5/2-i(sqrt(3))/2