What are the solutions to the equation x^3-12x+7=0 ?

The solutions to the equation x^3-12x+7=0 are x\approx 0.60146…,x\approx 3.12398…,x\approx-3.72544…

Find the zeros of x^3-12x+7=0

The zeros of x^3-12x+7=0 are x\approx 0.60146…,x\approx 3.12398…,x\approx-3.72544…

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x^{3} - 12 x + 7 = 0

x \approx 0.60146 \dots, x \approx 3.12398 \dots, x \approx - 3.72544 \dots

Solution steps

x^{3} - 12 x + 7 = 0

Find one solution for

x^{3} - 12 x + 7 = 0

using Newton-Raphson:

x \approx 0.60146 \dots

Apply long division:

\frac{x ^{3} - 12 x + 7}{x - 0.60146 \dots} = x^{2} + 0.60146 \dots x - 11.63823 \dots

x^{2} + 0.60146 \dots x - 11.63823 \dots \approx 0

Find one solution for

x^{2} + 0.60146 \dots x - 11.63823 \dots = 0

using Newton-Raphson:

x \approx 3.12398 \dots

Apply long division:

\frac{x ^{2} + 0.60146 \dots x - 11.63823 \dots}{x - 3.12398 \dots} = x + 3.72544 \dots

x + 3.72544 \dots \approx 0

x \approx - 3.72544 \dots

The solutions are

x \approx 0.60146 \dots, x \approx 3.12398 \dots, x \approx - 3.72544 \dots

- 2 x (x + 8) (x^{2} - 9) = 0

2^{24} = (2 y)^{3}

5 x^{3} + 4 x^{2} - x = 0

5 x^{3} + 25 x^{2} + 62 x - 6 = 0

10 = 3 x^{3} - 2

What are the solutions to the equation x^3-12x+7=0 ?
The solutions to the equation x^3-12x+7=0 are x\approx 0.60146…,x\approx 3.12398…,x\approx-3.72544…
Find the zeros of x^3-12x+7=0
The zeros of x^3-12x+7=0 are x\approx 0.60146…,x\approx 3.12398…,x\approx-3.72544…