What are the solutions to the equation x^3-3x^2+7x-21=0 ?

The solutions to the equation x^3-3x^2+7x-21=0 are x=3,x=sqrt(7)i,x=-sqrt(7)i

Find the zeros of x^3-3x^2+7x-21=0

The zeros of x^3-3x^2+7x-21=0 are x=3,x=sqrt(7)i,x=-sqrt(7)i

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x^{3} - 3 x^{2} + 7 x - 21 = 0

x = 3, x = 7 i, x = - 7 i

Solution steps

x^{3} - 3 x^{2} + 7 x - 21 = 0

Factor

x^{3} - 3 x^{2} + 7 x - 21 : (x - 3) (x^{2} + 7)

(x - 3) (x^{2} + 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0 or x^{2} + 7 = 0

Solve

x - 3 = 0 : x = 3

Solve

x^{2} + 7 = 0 : x = 7 i, x = - 7 i

The solutions are

x = 3, x = 7 i, x = - 7 i

r^{3} + 1 = 0

x^{5} = 32 i

- 2 x^{3} - 2 x^{2} + 1 = 0

12500 = 10000 (1 + X)^{10}

x^{4} - 1 0^{2} + 16 = 0

What are the solutions to the equation x^3-3x^2+7x-21=0 ?
The solutions to the equation x^3-3x^2+7x-21=0 are x=3,x=sqrt(7)i,x=-sqrt(7)i
Find the zeros of x^3-3x^2+7x-21=0
The zeros of x^3-3x^2+7x-21=0 are x=3,x=sqrt(7)i,x=-sqrt(7)i