What are the solutions to the equation (1+x/4)^4-1=0 ?

The solutions to the equation (1+x/4)^4-1=0 are x=0,x=-8

Find the zeros of (1+x/4)^4-1=0

The zeros of (1+x/4)^4-1=0 are x=0,x=-8

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(1 + \frac{x}{4})^{4} - 1 = 0

x = 0, x = - 8

Solution steps

(1 + \frac{x}{4})^{4} - 1 = 0

Move

1

to the right side

(1 + \frac{x}{4})^{4} = 1

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

x = 0, x = - 8

5 x^{4} - 11 x^{2} - 4 x + 1 = 0

r^{4} - 5 r^{2} + 4 = 0

x^{5} - 3 x^{3} = 0

6 x^{3} - 23 x^{2} + 26 x - 8 = 0

x^{5} = - 13

What are the solutions to the equation (1+x/4)^4-1=0 ?
The solutions to the equation (1+x/4)^4-1=0 are x=0,x=-8
Find the zeros of (1+x/4)^4-1=0
The zeros of (1+x/4)^4-1=0 are x=0,x=-8