What are the solutions to the equation 1+y^3=0 ?

The solutions to the equation 1+y^3=0 are y=-1,y= 1/2-(sqrt(3))/2 i,y= 1/2+(sqrt(3))/2 i

Find the zeros of 1+y^3=0

The zeros of 1+y^3=0 are y=-1,y= 1/2-(sqrt(3))/2 i,y= 1/2+(sqrt(3))/2 i

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1 + y^{3} = 0

y = - 1, y = \frac{1}{2} - \frac{3}{2} i, y = \frac{1}{2} + \frac{3}{2} i

Solution steps

1 + y^{3} = 0

Move

1

to the right side

y^{3} = - 1

For

x^{3} = f (a)

the solutions are

Simplify

y = - 1, y = \frac{1}{2} - \frac{3}{2} i, y = \frac{1}{2} + \frac{3}{2} i

k^{4} - 100 k^{2} = 0

x^{3} - 5 x^{2} + 7 x - 35 = 0

5 x = 8 x^{15}

m^{3} - 9 m^{2} + 15 m + 25 = 0

5 x^{3} + 3 x^{2} + 3 x + 1 = - 23 x^{3}

What are the solutions to the equation 1+y^3=0 ?
The solutions to the equation 1+y^3=0 are y=-1,y= 1/2-(sqrt(3))/2 i,y= 1/2+(sqrt(3))/2 i
Find the zeros of 1+y^3=0
The zeros of 1+y^3=0 are y=-1,y= 1/2-(sqrt(3))/2 i,y= 1/2+(sqrt(3))/2 i