What are the solutions to the equation m^3-9m^2+15m+25=0 ?

The solutions to the equation m^3-9m^2+15m+25=0 are m=-1,m=5

Find the zeros of m^3-9m^2+15m+25=0

The zeros of m^3-9m^2+15m+25=0 are m=-1,m=5

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m^{3} - 9 m^{2} + 15 m + 25 = 0

m = - 1, m = 5

Solution steps

m^{3} - 9 m^{2} + 15 m + 25 = 0

Factor

m^{3} - 9 m^{2} + 15 m + 25 : (m + 1) (m - 5)^{2}

(m + 1) (m - 5)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

m + 1 = 0 or m - 5 = 0

Solve

m + 1 = 0 : m = - 1

Solve

m - 5 = 0 : m = 5

The solutions are

m = - 1, m = 5

5 x^{3} + 3 x^{2} + 3 x + 1 = - 23 x^{3}

(1 + x + x^{2})^{2} = 0

3 = (1 + x)^{12}

a = \frac{1}{2} x^{5} x^{8}

k^{3} - 3 k^{2} - 16 k + 48 = 0

What are the solutions to the equation m^3-9m^2+15m+25=0 ?
The solutions to the equation m^3-9m^2+15m+25=0 are m=-1,m=5
Find the zeros of m^3-9m^2+15m+25=0
The zeros of m^3-9m^2+15m+25=0 are m=-1,m=5