What are the solutions to the equation 3=(1+x)^{12} ?

The solutions to the equation 3=(1+x)^{12} are x=\sqrt[12]{3}-1,x=-\sqrt[12]{3}-1

Find the zeros of 3=(1+x)^{12}

The zeros of 3=(1+x)^{12} are x=\sqrt[12]{3}-1,x=-\sqrt[12]{3}-1

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3 = (1 + x)^{12}

Decimal Notation

x = 0.09587 \dots, x = - 2.09587 \dots

Solution steps

3 = (1 + x)^{12}

Switch sides

(1 + x)^{12} = 3

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

a = \frac{1}{2} x^{5} x^{8}

k^{3} - 3 k^{2} - 16 k + 48 = 0

3 x^{3} + 7 x^{2} = 6 x

y^{4} - 37 y^{2} = - 36

5 - x^{3} = - 15

What are the solutions to the equation 3=(1+x)^{12} ?
The solutions to the equation 3=(1+x)^{12} are x=\sqrt[12]{3}-1,x=-\sqrt[12]{3}-1
Find the zeros of 3=(1+x)^{12}
The zeros of 3=(1+x)^{12} are x=\sqrt[12]{3}-1,x=-\sqrt[12]{3}-1