What are the solutions to the equation 3x^3+7x^2=6x ?

The solutions to the equation 3x^3+7x^2=6x are x=0,x= 2/3 ,x=-3

Find the zeros of 3x^3+7x^2=6x

The zeros of 3x^3+7x^2=6x are x=0,x= 2/3 ,x=-3

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3 x^{3} + 7 x^{2} = 6 x

x = 0, x = \frac{2}{3}, x = - 3

Decimal Notation

x = 0, x = 0.66666 \dots, x = - 3

Solution steps

3 x^{3} + 7 x^{2} = 6 x

Move

6 x

to the left side

3 x^{3} + 7 x^{2} - 6 x = 0

Factor

3 x^{3} + 7 x^{2} - 6 x : x (3 x - 2) (x + 3)

x (3 x - 2) (x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 3 x - 2 = 0 or x + 3 = 0

Solve

3 x - 2 = 0 : x = \frac{2}{3}

Solve

x + 3 = 0 : x = - 3

The solutions are

x = 0, x = \frac{2}{3}, x = - 3

y^{4} - 37 y^{2} = - 36

5 - x^{3} = - 15

x^{3} + 7 x^{2} - 16 x - 112 = 0

x^{2} + x - 43 = 3 x^{4}

x^{3} + 9 x + 10 = 0

What are the solutions to the equation 3x^3+7x^2=6x ?
The solutions to the equation 3x^3+7x^2=6x are x=0,x= 2/3 ,x=-3
Find the zeros of 3x^3+7x^2=6x
The zeros of 3x^3+7x^2=6x are x=0,x= 2/3 ,x=-3