What are the solutions to the equation x^3+7x^2-16x-112=0 ?

The solutions to the equation x^3+7x^2-16x-112=0 are x=-7,x=-4,x=4

Find the zeros of x^3+7x^2-16x-112=0

The zeros of x^3+7x^2-16x-112=0 are x=-7,x=-4,x=4

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x^{3} + 7 x^{2} - 16 x - 112 = 0

x = - 7, x = - 4, x = 4

Solution steps

x^{3} + 7 x^{2} - 16 x - 112 = 0

Factor

x^{3} + 7 x^{2} - 16 x - 112 : (x + 7) (x + 4) (x - 4)

(x + 7) (x + 4) (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 7 = 0 or x + 4 = 0 or x - 4 = 0

Solve

x + 7 = 0 : x = - 7

Solve

x + 4 = 0 : x = - 4

Solve

x - 4 = 0 : x = 4

The solutions are

x = - 7, x = - 4, x = 4

x^{2} + x - 43 = 3 x^{4}

x^{3} + 9 x + 10 = 0

x^{3} - x^{2} + 5 x - 3 = 0

(x^{2} - 9) (x^{2} + 1) = 0

x^{4} + 6 x^{3} - 9 x^{2} - 54 x + 81 = 0

What are the solutions to the equation x^3+7x^2-16x-112=0 ?
The solutions to the equation x^3+7x^2-16x-112=0 are x=-7,x=-4,x=4
Find the zeros of x^3+7x^2-16x-112=0
The zeros of x^3+7x^2-16x-112=0 are x=-7,x=-4,x=4