What are the solutions to the equation (x^2-9)(x^2+1)=0 ?

The solutions to the equation (x^2-9)(x^2+1)=0 are x=-3,x=3,x=i,x=-i

Find the zeros of (x^2-9)(x^2+1)=0

The zeros of (x^2-9)(x^2+1)=0 are x=-3,x=3,x=i,x=-i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x^{2} - 9) (x^{2} + 1) = 0

x = - 3, x = 3, x = i, x = - i

Solution steps

(x^{2} - 9) (x^{2} + 1) = 0

Factor

(x^{2} - 9) (x^{2} + 1) : (x + 3) (x - 3) (x^{2} + 1)

(x + 3) (x - 3) (x^{2} + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 3 = 0 or x - 3 = 0 or x^{2} + 1 = 0

Solve

x + 3 = 0 : x = - 3

Solve

x - 3 = 0 : x = 3

Solve

x^{2} + 1 = 0 : x = i, x = - i

The solutions are

x = - 3, x = 3, x = i, x = - i

x^{4} + 6 x^{3} - 9 x^{2} - 54 x + 81 = 0

x^{4} - 3 x^{3} = 0

x^{3} + 2 x^{2} - 36 x - 72 = 0

x (x - 2) (x + 2) = 0

13 e^{9} e + 4 = - 5 e + 14 + 13 e^{9}

What are the solutions to the equation (x^2-9)(x^2+1)=0 ?
The solutions to the equation (x^2-9)(x^2+1)=0 are x=-3,x=3,x=i,x=-i
Find the zeros of (x^2-9)(x^2+1)=0
The zeros of (x^2-9)(x^2+1)=0 are x=-3,x=3,x=i,x=-i