What is factor 64-a^4b^4 ?

The solution to factor 64-a^4b^4 is (8+a^2b^2)(8-a^2b^2)

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factor 64-a^4b^4

factor

64 - a^{4} b^{4}

(8 + a^{2} b^{2}) (8 - a^{2} b^{2})

Solution steps

64 - a^{4} b^{4}

64 = 8^{2}

a^{4} b^{4} = (a^{2} b^{2})^{2}

= 8^{2} - (a^{2} b^{2})^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

8^{2} - (a^{2} b^{2})^{2} = (8 + a^{2} b^{2}) (8 - a^{2} b^{2})

= (8 + a^{2} b^{2}) (8 - a^{2} b^{2})

v^{2} + 5 v + 4 = 0

x^{3} + 7 x^{2} + 16 x + 112

\frac{( 3 + 8 i ) ^{4}}{( 1 + i ) ^{10}}

s^{2} + 5 s + 100 = 0

∣ 2 - 3 x ∣ > 1

What is factor 64-a^4b^4 ?
The solution to factor 64-a^4b^4 is (8+a^2b^2)(8-a^2b^2)