What are the solutions to the equation x^3+2x^2-36x-72=0 ?

The solutions to the equation x^3+2x^2-36x-72=0 are x=-2,x=-6,x=6

Find the zeros of x^3+2x^2-36x-72=0

The zeros of x^3+2x^2-36x-72=0 are x=-2,x=-6,x=6

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x^{3} + 2 x^{2} - 36 x - 72 = 0

x = - 2, x = - 6, x = 6

Solution steps

x^{3} + 2 x^{2} - 36 x - 72 = 0

Factor

x^{3} + 2 x^{2} - 36 x - 72 : (x + 2) (x + 6) (x - 6)

(x + 2) (x + 6) (x - 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x + 6 = 0 or x - 6 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x + 6 = 0 : x = - 6

Solve

x - 6 = 0 : x = 6

The solutions are

x = - 2, x = - 6, x = 6

x (x - 2) (x + 2) = 0

13 e^{9} e + 4 = - 5 e + 14 + 13 e^{9}

x^{4} - 3 x^{3} + 4 x^{2} - 3 x + 1 = 0

4 x^{3} - 3 x^{2} = 0

9 y^{4} + 65 y^{2} - 144 = 0

What are the solutions to the equation x^3+2x^2-36x-72=0 ?
The solutions to the equation x^3+2x^2-36x-72=0 are x=-2,x=-6,x=6
Find the zeros of x^3+2x^2-36x-72=0
The zeros of x^3+2x^2-36x-72=0 are x=-2,x=-6,x=6