What are the solutions to the equation 0=2x^3+7x^2-21x-54 ?

The solutions to the equation 0=2x^3+7x^2-21x-54 are x=-2,x=3,x=-9/2

Find the zeros of 0=2x^3+7x^2-21x-54

The zeros of 0=2x^3+7x^2-21x-54 are x=-2,x=3,x=-9/2

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0 = 2 x^{3} + 7 x^{2} - 21 x - 54

x = - 2, x = 3, x = - \frac{9}{2}

Decimal Notation

x = - 2, x = 3, x = - 4.5

Solution steps

0 = 2 x^{3} + 7 x^{2} - 21 x - 54

Switch sides

2 x^{3} + 7 x^{2} - 21 x - 54 = 0

Factor

2 x^{3} + 7 x^{2} - 21 x - 54 : (x + 2) (x - 3) (2 x + 9)

(x + 2) (x - 3) (2 x + 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x - 3 = 0 or 2 x + 9 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x - 3 = 0 : x = 3

Solve

2 x + 9 = 0 : x = - \frac{9}{2}

The solutions are

x = - 2, x = 3, x = - \frac{9}{2}

39 = x^{5} + x + 5

z^{3} = \frac{1}{8} i

49 x^{4} - 25 x^{2} = 0

x^{(4)} - 4 x^{(2)} + 3 = 0

r^{4} + 9 r^{2} = 0

What are the solutions to the equation 0=2x^3+7x^2-21x-54 ?
The solutions to the equation 0=2x^3+7x^2-21x-54 are x=-2,x=3,x=-9/2
Find the zeros of 0=2x^3+7x^2-21x-54
The zeros of 0=2x^3+7x^2-21x-54 are x=-2,x=3,x=-9/2