What are the solutions to the equation x^2+3x-7/4 =0 ?

The solutions to the equation x^2+3x-7/4 =0 are x= 1/2 ,x=-7/2

Find the zeros of x^2+3x-7/4 =0

The zeros of x^2+3x-7/4 =0 are x= 1/2 ,x=-7/2

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x^{2} + 3 x - \frac{7}{4} = 0

x = \frac{1}{2}, x = - \frac{7}{2}

Decimal Notation

x = 0.5, x = - 3.5

Solution steps

x^{2} + 3 x - \frac{7}{4} = 0

Multiply both sides by

4

4 x^{2} + 12 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 4 ( - 7 )}{2 \cdot 4}

1 2^{2} - 4 \cdot 4 (- 7) = 16

x_{1, 2} = \frac{- 12 \pm 16}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 12 + 16}{2 \cdot 4}, x_{2} = \frac{- 12 - 16}{2 \cdot 4}

x = \frac{- 12 + 16}{2 \cdot 4} : \frac{1}{2}

x = \frac{- 12 - 16}{2 \cdot 4} : - \frac{7}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - \frac{7}{2}

(x - 8)^{2} = 48

\frac{b}{- 3} + 4 < 13

6 x^{2} - 3 = 7 x

∣ x - 3 ∣ - 4 = 5

4 w^{2} - 25

What are the solutions to the equation x^2+3x-7/4 =0 ?
The solutions to the equation x^2+3x-7/4 =0 are x= 1/2 ,x=-7/2
Find the zeros of x^2+3x-7/4 =0
The zeros of x^2+3x-7/4 =0 are x= 1/2 ,x=-7/2