What are the solutions to the equation 0=x^4-4x^2 ?

The solutions to the equation 0=x^4-4x^2 are x=2,x=-2,x=0

Find the zeros of 0=x^4-4x^2

The zeros of 0=x^4-4x^2 are x=2,x=-2,x=0

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0 = x^{4} - 4 x^{2}

x = 2, x = - 2, x = 0

Solution steps

0 = x^{4} - 4 x^{2}

Switch sides

x^{4} - 4 x^{2} = 0

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

u^{2} - 4 u = 0

Solve

u^{2} - 4 u = 0 : u = 4, u = 0

u = 4, u = 0

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = 4 : x = 2, x = - 2

Solve

x^{2} = 0 : x = 0

The solutions are

x = 2, x = - 2, x = 0

6 x^{4} - 7 x^{3} - x^{2} + 67 x - 105 = 0

x, f (x) =, (f (x) \circ g (x)) 5 - x^{3}

(x^{2} + 3 x)^{2} = 4 (x^{2} + 3 x)

(x - 1) (x + 1) (x + 2) = - 2

x^{2} (x - 2)^{2} (x - 1)^{2} = 0

What are the solutions to the equation 0=x^4-4x^2 ?
The solutions to the equation 0=x^4-4x^2 are x=2,x=-2,x=0
Find the zeros of 0=x^4-4x^2
The zeros of 0=x^4-4x^2 are x=2,x=-2,x=0