What are the solutions to the equation x^3+2x^2-7x=-4 ?

The solutions to the equation x^3+2x^2-7x=-4 are x=1,x=-4

Find the zeros of x^3+2x^2-7x=-4

The zeros of x^3+2x^2-7x=-4 are x=1,x=-4

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x^{3} + 2 x^{2} - 7 x = - 4

x = 1, x = - 4

Solution steps

x^{3} + 2 x^{2} - 7 x = - 4

Move

4

to the left side

x^{3} + 2 x^{2} - 7 x + 4 = 0

Factor

x^{3} + 2 x^{2} - 7 x + 4 : (x - 1)^{2} (x + 4)

(x - 1)^{2} (x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x + 4 = 0

Solve

x - 1 = 0 : x = 1

Solve

x + 4 = 0 : x = - 4

The solutions are

x = 1, x = - 4

(x + 2 i) (x - 2 i) (x - 5) = 0

5 x^{3} + 13 x^{2} - 56 x + 20 = 0

4 x^{3} + 42 x^{2} + 240 x + 800 = 0

x^{(4)} - 29 x^{(2)} + 100 = 0

- 2 x^{3} - 4 x^{2} + 10 x + 12 = 0

What are the solutions to the equation x^3+2x^2-7x=-4 ?
The solutions to the equation x^3+2x^2-7x=-4 are x=1,x=-4
Find the zeros of x^3+2x^2-7x=-4
The zeros of x^3+2x^2-7x=-4 are x=1,x=-4