What are the solutions to the equation x(x-3)^2=2x ?

The solutions to the equation x(x-3)^2=2x are x=0,x=3-sqrt(2),x=3+sqrt(2)

Find the zeros of x(x-3)^2=2x

The zeros of x(x-3)^2=2x are x=0,x=3-sqrt(2),x=3+sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x (x - 3)^{2} = 2 x

x = 0, x = 3 - 2, x = 3 + 2

Decimal Notation

x = 0, x = 1.58578 \dots, x = 4.41421 \dots

Solution steps

x (x - 3)^{2} = 2 x

Move

2 x

to the left side

x (x - 3)^{2} - 2 x = 0

Factor

x (x - 3)^{2} - 2 x : x (x - 3 + 2) (x - 3 - 2)

x (x - 3 + 2) (x - 3 - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 3 + 2 = 0 or x - 3 - 2 = 0

Solve

x - 3 + 2 = 0 : x = 3 - 2

Solve

x - 3 - 2 = 0 : x = 3 + 2

The solutions are

x = 0, x = 3 - 2, x = 3 + 2

(x - 3)^{7} = 64 (x - 3)^{4}

- 16 y - y^{3} + 32 = 0

x^{3} - 3 = - 30

(x - 1) (x - 2) (x + 1) = 0

8 t^{3} + 2 = 66

What are the solutions to the equation x(x-3)^2=2x ?
The solutions to the equation x(x-3)^2=2x are x=0,x=3-sqrt(2),x=3+sqrt(2)
Find the zeros of x(x-3)^2=2x
The zeros of x(x-3)^2=2x are x=0,x=3-sqrt(2),x=3+sqrt(2)