What are the solutions to the equation -16y-y^3+32=0 ?

The solutions to the equation -16y-y^3+32=0 are y\approx 1.69541…

Find the zeros of -16y-y^3+32=0

The zeros of -16y-y^3+32=0 are y\approx 1.69541…

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- 16 y - y^{3} + 32 = 0

y \approx 1.69541 \dots

Solution steps

- 16 y - y^{3} + 32 = 0

Write in the standard form

a_{n} x^{n} + \dots + a_{1} x + a_{0} = 0

- y^{3} - 16 y + 32 = 0

Find one solution for

- y^{3} - 16 y + 32 = 0

using Newton-Raphson:

y \approx 1.69541 \dots

Apply long division:

\frac{- y ^{3} - 16 y + 32}{y - 1.69541 \dots} = - y^{2} - 1.69541 \dots y - 18.87443 \dots

- y^{2} - 1.69541 \dots y - 18.87443 \dots \approx 0

Find one solution for

- y^{2} - 1.69541 \dots y - 18.87443 \dots = 0

using Newton-Raphson:

No Solution for

y \in R

The solution is

y \approx 1.69541 \dots

x^{3} - 3 = - 30

(x - 1) (x - 2) (x + 1) = 0

8 t^{3} + 2 = 66

2 x^{3} - 5 x^{2} + 4 x - 10 = 0

- 120 + 79 x - 16 x^{2} + x^{3} = 0

What are the solutions to the equation -16y-y^3+32=0 ?
The solutions to the equation -16y-y^3+32=0 are y\approx 1.69541…
Find the zeros of -16y-y^3+32=0
The zeros of -16y-y^3+32=0 are y\approx 1.69541…