What are the solutions to the equation -120+79x-16x^2+x^3=0 ?

The solutions to the equation -120+79x-16x^2+x^3=0 are x=3,x=5,x=8

Find the zeros of -120+79x-16x^2+x^3=0

The zeros of -120+79x-16x^2+x^3=0 are x=3,x=5,x=8

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- 120 + 79 x - 16 x^{2} + x^{3} = 0

x = 3, x = 5, x = 8

Solution steps

- 120 + 79 x - 16 x^{2} + x^{3} = 0

Write in the standard form

a_{n} x^{n} + \dots + a_{1} x + a_{0} = 0

x^{3} - 16 x^{2} + 79 x - 120 = 0

Factor

x^{3} - 16 x^{2} + 79 x - 120 : (x - 3) (x - 5) (x - 8)

(x - 3) (x - 5) (x - 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0 or x - 5 = 0 or x - 8 = 0

Solve

x - 3 = 0 : x = 3

Solve

x - 5 = 0 : x = 5

Solve

x - 8 = 0 : x = 8

The solutions are

x = 3, x = 5, x = 8

2 \cdot (x^{3}) - x = 0.5

(x) = 5 x^{5} - 3 x^{3} + 4 x + 5

x, x^{4} - 18 x^{2} + 81 = 0

(4^{2} + x)^{4} = 16

2 x^{3} + 3 x^{2} + 3 + 2 x = 0

What are the solutions to the equation -120+79x-16x^2+x^3=0 ?
The solutions to the equation -120+79x-16x^2+x^3=0 are x=3,x=5,x=8
Find the zeros of -120+79x-16x^2+x^3=0
The zeros of -120+79x-16x^2+x^3=0 are x=3,x=5,x=8