Solution
Solution
Solution steps
Factor
Using the Zero Factor Principle: If then or
Solve
Solve
Solve
The solutions are
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Frequently Asked Questions (FAQ)
What are the solutions to the equation 12(k^3-4k^2+k+6)=0 ?
The solutions to the equation 12(k^3-4k^2+k+6)=0 are k=-1,k=2,k=3Find the zeros of 12(k^3-4k^2+k+6)=0
The zeros of 12(k^3-4k^2+k+6)=0 are k=-1,k=2,k=3