What are the solutions to the equation 27=r^3 ?

The solutions to the equation 27=r^3 are r=3,r=-3/2+(3sqrt(3))/2 i,r=-3/2-(3sqrt(3))/2 i

Find the zeros of 27=r^3

The zeros of 27=r^3 are r=3,r=-3/2+(3sqrt(3))/2 i,r=-3/2-(3sqrt(3))/2 i

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27 = r^{3}

r = 3, r = - \frac{3}{2} + \frac{3 3}{2} i, r = - \frac{3}{2} - \frac{3 3}{2} i

Solution steps

27 = r^{3}

Switch sides

r^{3} = 27

For

x^{3} = f (a)

the solutions are

Simplify

r = 3, r = - \frac{3}{2} + \frac{3 3}{2} i, r = - \frac{3}{2} - \frac{3 3}{2} i

28 x^{3} + 16 x^{2} - 80 x = 0

7.8 x^{2} + x^{3} - 0.0317 = 0

x^{5} - 2 x^{4} + x^{3} = 0

(- x)^{8} = - (x)^{8}

735 = 8 (1 + x)^{29}

What are the solutions to the equation 27=r^3 ?
The solutions to the equation 27=r^3 are r=3,r=-3/2+(3sqrt(3))/2 i,r=-3/2-(3sqrt(3))/2 i
Find the zeros of 27=r^3
The zeros of 27=r^3 are r=3,r=-3/2+(3sqrt(3))/2 i,r=-3/2-(3sqrt(3))/2 i