What are the solutions to the equation 1x^4+21x^2-100=0 ?

The solutions to the equation 1x^4+21x^2-100=0 are x=2,x=-2,x=5i,x=-5i

Find the zeros of 1x^4+21x^2-100=0

The zeros of 1x^4+21x^2-100=0 are x=2,x=-2,x=5i,x=-5i

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1 x^{4} + 21 x^{2} - 100 = 0

x = 2, x = - 2, x = 5 i, x = - 5 i

Solution steps

1 \cdot x^{4} + 21 x^{2} - 100 = 0

Refine

x^{4} + 21 x^{2} - 100 = 0

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

u^{2} + 21 u - 100 = 0

Solve

u^{2} + 21 u - 100 = 0 : u = 4, u = - 25

u = 4, u = - 25

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = 4 : x = 2, x = - 2

Solve

x^{2} = - 25 : x = 5 i, x = - 5 i

The solutions are

x = 2, x = - 2, x = 5 i, x = - 5 i

t^{3} = 216

18 q^{3} - 8 q = 0

0 = x^{3} + 4 x^{2} - 9 x - 36

2 x^{3} - 5 x^{2} - 14 x + 8 = 0

x^{4} + 10 x^{3} + 25 x^{2} = 0

What are the solutions to the equation 1x^4+21x^2-100=0 ?
The solutions to the equation 1x^4+21x^2-100=0 are x=2,x=-2,x=5i,x=-5i
Find the zeros of 1x^4+21x^2-100=0
The zeros of 1x^4+21x^2-100=0 are x=2,x=-2,x=5i,x=-5i