What are the solutions to the equation 0=x^3+4x^2-9x-36 ?

The solutions to the equation 0=x^3+4x^2-9x-36 are x=-4,x=-3,x=3

Find the zeros of 0=x^3+4x^2-9x-36

The zeros of 0=x^3+4x^2-9x-36 are x=-4,x=-3,x=3

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0 = x^{3} + 4 x^{2} - 9 x - 36

x = - 4, x = - 3, x = 3

Solution steps

0 = x^{3} + 4 x^{2} - 9 x - 36

Switch sides

x^{3} + 4 x^{2} - 9 x - 36 = 0

Factor

x^{3} + 4 x^{2} - 9 x - 36 : (x + 4) (x + 3) (x - 3)

(x + 4) (x + 3) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 4 = 0 or x + 3 = 0 or x - 3 = 0

Solve

x + 4 = 0 : x = - 4

Solve

x + 3 = 0 : x = - 3

Solve

x - 3 = 0 : x = 3

The solutions are

x = - 4, x = - 3, x = 3

2 x^{3} - 5 x^{2} - 14 x + 8 = 0

x^{4} + 10 x^{3} + 25 x^{2} = 0

5 c^{3} + 10 c^{2} - 75 c = 0

(s - 1)^{2} (s - 3)^{2} = 0

140 π = 2 π r^{10}

What are the solutions to the equation 0=x^3+4x^2-9x-36 ?
The solutions to the equation 0=x^3+4x^2-9x-36 are x=-4,x=-3,x=3
Find the zeros of 0=x^3+4x^2-9x-36
The zeros of 0=x^3+4x^2-9x-36 are x=-4,x=-3,x=3