What are the solutions to the equation 4x^3+x^2-4x-1=0 ?

The solutions to the equation 4x^3+x^2-4x-1=0 are x=-1/4 ,x=-1,x=1

Find the zeros of 4x^3+x^2-4x-1=0

The zeros of 4x^3+x^2-4x-1=0 are x=-1/4 ,x=-1,x=1

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4 x^{3} + x^{2} - 4 x - 1 = 0

x = - \frac{1}{4}, x = - 1, x = 1

Decimal Notation

x = - 0.25, x = - 1, x = 1

Solution steps

4 x^{3} + x^{2} - 4 x - 1 = 0

Factor

4 x^{3} + x^{2} - 4 x - 1 : (4 x + 1) (x + 1) (x - 1)

(4 x + 1) (x + 1) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

4 x + 1 = 0 or x + 1 = 0 or x - 1 = 0

Solve

4 x + 1 = 0 : x = - \frac{1}{4}

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

The solutions are

x = - \frac{1}{4}, x = - 1, x = 1

(1 + x)^{12} = 10968

- 2 x^{2} + x^{3} + 1 = 0

19.6 y^{3} - 40.57 y^{2} + 25 = 0

(8 x^{7}) + (8 x^{4}) = 8 x (x)

x^{4} + i x = i x - i + 3

What are the solutions to the equation 4x^3+x^2-4x-1=0 ?
The solutions to the equation 4x^3+x^2-4x-1=0 are x=-1/4 ,x=-1,x=1
Find the zeros of 4x^3+x^2-4x-1=0
The zeros of 4x^3+x^2-4x-1=0 are x=-1/4 ,x=-1,x=1