What are the solutions to the equation 27=t^3 ?

The solutions to the equation 27=t^3 are t=3,t=-3/2+(3sqrt(3))/2 i,t=-3/2-(3sqrt(3))/2 i

Find the zeros of 27=t^3

The zeros of 27=t^3 are t=3,t=-3/2+(3sqrt(3))/2 i,t=-3/2-(3sqrt(3))/2 i

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27 = t^{3}

t = 3, t = - \frac{3}{2} + \frac{3 3}{2} i, t = - \frac{3}{2} - \frac{3 3}{2} i

Solution steps

27 = t^{3}

Switch sides

t^{3} = 27

For

x^{3} = f (a)

the solutions are

Simplify

t = 3, t = - \frac{3}{2} + \frac{3 3}{2} i, t = - \frac{3}{2} - \frac{3 3}{2} i

(r^{2} + 1)^{4} = 0

- 5 x^{1} + 8 x^{2} + 10 x^{3} = - 8

3 x^{3} - 2 = 0

x^{4} - 6 x^{2} + 8 x - 1 = 0

a, (a - b)^{3} = 0

What are the solutions to the equation 27=t^3 ?
The solutions to the equation 27=t^3 are t=3,t=-3/2+(3sqrt(3))/2 i,t=-3/2-(3sqrt(3))/2 i
Find the zeros of 27=t^3
The zeros of 27=t^3 are t=3,t=-3/2+(3sqrt(3))/2 i,t=-3/2-(3sqrt(3))/2 i