What are the solutions to the equation 3x^5+18x^4-21x^3=0 ?

The solutions to the equation 3x^5+18x^4-21x^3=0 are x=0,x=1,x=-7

Find the zeros of 3x^5+18x^4-21x^3=0

The zeros of 3x^5+18x^4-21x^3=0 are x=0,x=1,x=-7

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3 x^{5} + 18 x^{4} - 21 x^{3} = 0

x = 0, x = 1, x = - 7

Solution steps

3 x^{5} + 18 x^{4} - 21 x^{3} = 0

Factor

3 x^{5} + 18 x^{4} - 21 x^{3} : 3 x^{3} (x - 1) (x + 7)

3 x^{3} (x - 1) (x + 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 1 = 0 or x + 7 = 0

Solve

x - 1 = 0 : x = 1

Solve

x + 7 = 0 : x = - 7

The solutions are

x = 0, x = 1, x = - 7

- 4 r^{5} + 4 r^{4} + 0.25 r - 0.25 = 0

x^{8} + 36 = x - 3 + 25

m, L = 12 m^{3}

x^{3} 2 x^{2} - 11 x - 12 = 0

- x^{3} + 54 x^{2} - 6 x + 25 = 0

What are the solutions to the equation 3x^5+18x^4-21x^3=0 ?
The solutions to the equation 3x^5+18x^4-21x^3=0 are x=0,x=1,x=-7
Find the zeros of 3x^5+18x^4-21x^3=0
The zeros of 3x^5+18x^4-21x^3=0 are x=0,x=1,x=-7