What are the solutions to the equation (x-3)^2=1 ?

The solutions to the equation (x-3)^2=1 are x=4,x=2

Find the zeros of (x-3)^2=1

The zeros of (x-3)^2=1 are x=4,x=2

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(x - 3)^{2} = 1

x = 4, x = 2

Solution steps

(x - 3)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = 1 : x = 4

Solve

x - 3 = - 1 : x = 2

The solutions to the quadratic equation are:

x = 4, x = 2

84 = x^{2} + 8 x

6 x^{2} + x - 2

\frac{16}{3} + 5

ln (\frac{1}{e ^{8}})

\frac{1}{4} x^{2} = 1

What are the solutions to the equation (x-3)^2=1 ?
The solutions to the equation (x-3)^2=1 are x=4,x=2
Find the zeros of (x-3)^2=1
The zeros of (x-3)^2=1 are x=4,x=2