What are the solutions to the equation 2x^3-6x^2+5x-1=0 ?

The solutions to the equation 2x^3-6x^2+5x-1=0 are x=1,x=(2+sqrt(2))/2 ,x=(2-sqrt(2))/2

Find the zeros of 2x^3-6x^2+5x-1=0

The zeros of 2x^3-6x^2+5x-1=0 are x=1,x=(2+sqrt(2))/2 ,x=(2-sqrt(2))/2

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2 x^{3} - 6 x^{2} + 5 x - 1 = 0

x = 1, x = \frac{2 + 2}{2}, x = \frac{2 - 2}{2}

Decimal Notation

x = 1, x = 1.70710 \dots, x = 0.29289 \dots

Solution steps

2 x^{3} - 6 x^{2} + 5 x - 1 = 0

Factor

2 x^{3} - 6 x^{2} + 5 x - 1 : (x - 1) (2 x^{2} - 4 x + 1)

(x - 1) (2 x^{2} - 4 x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or 2 x^{2} - 4 x + 1 = 0

Solve

x - 1 = 0 : x = 1

Solve

2 x^{2} - 4 x + 1 = 0 : x = \frac{2 + 2}{2}, x = \frac{2 - 2}{2}

The solutions are

x = 1, x = \frac{2 + 2}{2}, x = \frac{2 - 2}{2}

- x^{3} + 7 x^{2} + 17 x + 9 = 0

- 3 x^{10} = 5 x - 8

(2 n + 2) (n + 1) (n + 2) = 160

x^{4} - 12 x^{2} = - 32

1200 = 600 \cdot (1 + x)^{10}

What are the solutions to the equation 2x^3-6x^2+5x-1=0 ?
The solutions to the equation 2x^3-6x^2+5x-1=0 are x=1,x=(2+sqrt(2))/2 ,x=(2-sqrt(2))/2
Find the zeros of 2x^3-6x^2+5x-1=0
The zeros of 2x^3-6x^2+5x-1=0 are x=1,x=(2+sqrt(2))/2 ,x=(2-sqrt(2))/2