What are the solutions to the equation x=x-x^3-4*x^2+10 ?

The solutions to the equation x=x-x^3-4*x^2+10 are x\approx 1.36523…

Find the zeros of x=x-x^3-4*x^2+10

The zeros of x=x-x^3-4*x^2+10 are x\approx 1.36523…

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x = x - x^{3} - 4 \cdot x^{2} + 10

x \approx 1.36523 \dots

Solution steps

x = x - x^{3} - 4 x^{2} + 10

Switch sides

x - x^{3} - 4 x^{2} + 10 = x

Move

x

to the left side

- x^{3} - 4 x^{2} + 10 = 0

Find one solution for

- x^{3} - 4 x^{2} + 10 = 0

using Newton-Raphson:

x \approx 1.36523 \dots

Apply long division:

\frac{- x ^{3} - 4 x ^{2} + 10}{x - 1.36523 \dots} = - x^{2} - 5.36523 \dots x - 7.32477 \dots

- x^{2} - 5.36523 \dots x - 7.32477 \dots \approx 0

Find one solution for

- x^{2} - 5.36523 \dots x - 7.32477 \dots = 0

using Newton-Raphson:

No Solution for

x \in R

The solution is

x \approx 1.36523 \dots

0 = x (x + 5) (x^{2} - 8 x - 19)

x^{4} + 2 x^{3} - 9 x^{2} - 10 x - 24 = 0

m, m^{3} - 3 m - 26 = 0

2 x^{4} - 3 x^{3} - 15 x^{2} + 32 x - 12 = 0

x^{3} - x + 13 = 0

What are the solutions to the equation x=x-x^3-4*x^2+10 ?
The solutions to the equation x=x-x^3-4*x^2+10 are x\approx 1.36523…
Find the zeros of x=x-x^3-4*x^2+10
The zeros of x=x-x^3-4*x^2+10 are x\approx 1.36523…