What are the solutions to the equation x^3-5x^2+5x+7=7 ?

The solutions to the equation x^3-5x^2+5x+7=7 are x=0,x=(5+sqrt(5))/2 ,x=(5-sqrt(5))/2

Find the zeros of x^3-5x^2+5x+7=7

The zeros of x^3-5x^2+5x+7=7 are x=0,x=(5+sqrt(5))/2 ,x=(5-sqrt(5))/2

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x^{3} - 5 x^{2} + 5 x + 7 = 7

x = 0, x = \frac{5 + 5}{2}, x = \frac{5 - 5}{2}

Decimal Notation

x = 0, x = 3.61803 \dots, x = 1.38196 \dots

Solution steps

x^{3} - 5 x^{2} + 5 x + 7 = 7

Move

7

to the right side

x^{3} - 5 x^{2} + 5 x = 0

Factor

x^{3} - 5 x^{2} + 5 x : x (x^{2} - 5 x + 5)

x (x^{2} - 5 x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x^{2} - 5 x + 5 = 0

Solve

x^{2} - 5 x + 5 = 0 : x = \frac{5 + 5}{2}, x = \frac{5 - 5}{2}

The solutions are

x = 0, x = \frac{5 + 5}{2}, x = \frac{5 - 5}{2}

x^{8} + 8 x + 16 = 0

9 + 3 a^{3} = 12

x^{4} = 2 x^{3} + 1

(1.01)^{5} (1 + r)^{5} = 2

2 x^{4} + x^{2} - 15 = 0

What are the solutions to the equation x^3-5x^2+5x+7=7 ?
The solutions to the equation x^3-5x^2+5x+7=7 are x=0,x=(5+sqrt(5))/2 ,x=(5-sqrt(5))/2
Find the zeros of x^3-5x^2+5x+7=7
The zeros of x^3-5x^2+5x+7=7 are x=0,x=(5+sqrt(5))/2 ,x=(5-sqrt(5))/2