What are the solutions to the equation 9+3a^3=12 ?

The solutions to the equation 9+3a^3=12 are a=1,a=-1/2+(sqrt(3))/2 i,a=-1/2-(sqrt(3))/2 i

Find the zeros of 9+3a^3=12

The zeros of 9+3a^3=12 are a=1,a=-1/2+(sqrt(3))/2 i,a=-1/2-(sqrt(3))/2 i

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9 + 3 a^{3} = 12

a = 1, a = - \frac{1}{2} + \frac{3}{2} i, a = - \frac{1}{2} - \frac{3}{2} i

Solution steps

9 + 3 a^{3} = 12

Move

9

to the right side

3 a^{3} = 3

Divide both sides by

3

a^{3} = 1

For

x^{3} = f (a)

the solutions are

a = 1, a = \frac{- 1 + 3 i}{2}, a = \frac{- 1 - 3 i}{2}

Simplify

\frac{- 1 + 3 i}{2} : - \frac{1}{2} + \frac{3}{2} i

Simplify

\frac{- 1 - 3 i}{2} : - \frac{1}{2} - \frac{3}{2} i

a = 1, a = - \frac{1}{2} + \frac{3}{2} i, a = - \frac{1}{2} - \frac{3}{2} i

x^{4} = 2 x^{3} + 1

(1.01)^{5} (1 + r)^{5} = 2

2 x^{4} + x^{2} - 15 = 0

x^{3} - 2 x^{2} - 55 x + 6 = 0

- 3 x^{4} + 18 x^{3} + 48 x^{2} = 0

What are the solutions to the equation 9+3a^3=12 ?
The solutions to the equation 9+3a^3=12 are a=1,a=-1/2+(sqrt(3))/2 i,a=-1/2-(sqrt(3))/2 i
Find the zeros of 9+3a^3=12
The zeros of 9+3a^3=12 are a=1,a=-1/2+(sqrt(3))/2 i,a=-1/2-(sqrt(3))/2 i