What are the solutions to the equation 3x^2(x+1)^2-x(x+1)^3=0 ?

The solutions to the equation 3x^2(x+1)^2-x(x+1)^3=0 are x=0,x=-1,x= 1/2

Find the zeros of 3x^2(x+1)^2-x(x+1)^3=0

The zeros of 3x^2(x+1)^2-x(x+1)^3=0 are x=0,x=-1,x= 1/2

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3 x^{2} (x + 1)^{2} - x (x + 1)^{3} = 0

x = 0, x = - 1, x = \frac{1}{2}

Decimal Notation

x = 0, x = - 1, x = 0.5

Solution steps

3 x^{2} (x + 1)^{2} - x (x + 1)^{3} = 0

Factor

3 x^{2} (x + 1)^{2} - x (x + 1)^{3} : x (x + 1)^{2} (2 x - 1)

x (x + 1)^{2} (2 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 1 = 0 or 2 x - 1 = 0

Solve

x + 1 = 0 : x = - 1

Solve

2 x - 1 = 0 : x = \frac{1}{2}

The solutions are

x = 0, x = - 1, x = \frac{1}{2}

49 t^{4} + 44 t^{2} - 5 = 0

12 x (x^{2} - 1)^{2} = 0

x^{4} = - 16 i

\frac{64}{81} = 4 q^{4}

(- 3) (x) = 3 x^{3} + 5

What are the solutions to the equation 3x^2(x+1)^2-x(x+1)^3=0 ?
The solutions to the equation 3x^2(x+1)^2-x(x+1)^3=0 are x=0,x=-1,x= 1/2
Find the zeros of 3x^2(x+1)^2-x(x+1)^3=0
The zeros of 3x^2(x+1)^2-x(x+1)^3=0 are x=0,x=-1,x= 1/2