What are the solutions to the equation -3m^4=48m^2 ?

The solutions to the equation -3m^4=48m^2 are m=0,m=4i,m=-4i

Find the zeros of -3m^4=48m^2

The zeros of -3m^4=48m^2 are m=0,m=4i,m=-4i

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- 3 m^{4} = 48 m^{2}

m = 0, m = 4 i, m = - 4 i

Solution steps

- 3 m^{4} = 48 m^{2}

Move

48 m^{2}

to the left side

- 3 m^{4} - 48 m^{2} = 0

Factor

- 3 m^{4} - 48 m^{2} : - 3 m^{2} (m^{2} + 16)

- 3 m^{2} (m^{2} + 16) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

m = 0 or m^{2} + 16 = 0

Solve

m^{2} + 16 = 0 : m = 4 i, m = - 4 i

The solutions are

m = 0, m = 4 i, m = - 4 i

4 r^{4} - 64 r^{2} = 0

5 x^{3} - 10 x^{2} + 10 x = 0

5 y^{3} - 29 y^{2} - 6 y = 0

2 x^{3} - 23 = 35

x^{3} = 4 x^{2} + 5 x

What are the solutions to the equation -3m^4=48m^2 ?
The solutions to the equation -3m^4=48m^2 are m=0,m=4i,m=-4i
Find the zeros of -3m^4=48m^2
The zeros of -3m^4=48m^2 are m=0,m=4i,m=-4i