What are the solutions to the equation x(x^2-8x+4)=0 ?

The solutions to the equation x(x^2-8x+4)=0 are x=0,x=2(2+sqrt(3)),x=2(2-sqrt(3))

Find the zeros of x(x^2-8x+4)=0

The zeros of x(x^2-8x+4)=0 are x=0,x=2(2+sqrt(3)),x=2(2-sqrt(3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x (x^{2} - 8 x + 4) = 0

x = 0, x = 2 (2 + 3), x = 2 (2 - 3)

Decimal Notation

x = 0, x = 7.46410 \dots, x = 0.53589 \dots

Solution steps

x (x^{2} - 8 x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x^{2} - 8 x + 4 = 0

Solve

x^{2} - 8 x + 4 = 0 : x = 2 (2 + 3), x = 2 (2 - 3)

The solutions are

x = 0, x = 2 (2 + 3), x = 2 (2 - 3)

x^{4} - 6 x^{2} - 7 x - 6 = 0

x^{4} - 8 x^{3} + 21 x^{2} - 20 x + 5 = 0

b^{3} - 125 = 0

4 x^{3} - 8 x^{2} + 5 x - 73 = 0

x (x - 2) (x + 5) = 0

What are the solutions to the equation x(x^2-8x+4)=0 ?
The solutions to the equation x(x^2-8x+4)=0 are x=0,x=2(2+sqrt(3)),x=2(2-sqrt(3))
Find the zeros of x(x^2-8x+4)=0
The zeros of x(x^2-8x+4)=0 are x=0,x=2(2+sqrt(3)),x=2(2-sqrt(3))