What are the solutions to the equation 0=x^3-x^2-25x+25 ?

The solutions to the equation 0=x^3-x^2-25x+25 are x=1,x=-5,x=5

Find the zeros of 0=x^3-x^2-25x+25

The zeros of 0=x^3-x^2-25x+25 are x=1,x=-5,x=5

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0 = x^{3} - x^{2} - 25 x + 25

x = 1, x = - 5, x = 5

Solution steps

0 = x^{3} - x^{2} - 25 x + 25

Switch sides

x^{3} - x^{2} - 25 x + 25 = 0

Factor

x^{3} - x^{2} - 25 x + 25 : (x - 1) (x + 5) (x - 5)

(x - 1) (x + 5) (x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x + 5 = 0 or x - 5 = 0

Solve

x - 1 = 0 : x = 1

Solve

x + 5 = 0 : x = - 5

Solve

x - 5 = 0 : x = 5

The solutions are

x = 1, x = - 5, x = 5

x^{2} + x^{4} - 8 = 88

a^{4} + 6 a^{3} + 11 a^{2} + 6 a + 1 = 0

h^{4} - 2 = 1

x^{2} (x - 1) + 2 x = 0

20 x^{3} + 12 x^{2} - 12 x - 2 = 0

What are the solutions to the equation 0=x^3-x^2-25x+25 ?
The solutions to the equation 0=x^3-x^2-25x+25 are x=1,x=-5,x=5
Find the zeros of 0=x^3-x^2-25x+25
The zeros of 0=x^3-x^2-25x+25 are x=1,x=-5,x=5