What are the solutions to the equation 2x^3+72=200 ?

The solutions to the equation 2x^3+72=200 are x=4,x=-2+2sqrt(3)i,x=-2-2sqrt(3)i

Find the zeros of 2x^3+72=200

The zeros of 2x^3+72=200 are x=4,x=-2+2sqrt(3)i,x=-2-2sqrt(3)i

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2 x^{3} + 72 = 200

x = 4, x = - 2 + 23 i, x = - 2 - 23 i

Solution steps

2 x^{3} + 72 = 200

Move

72

to the right side

2 x^{3} = 128

Divide both sides by

2

x^{3} = 64

For

x^{3} = f (a)

the solutions are

Simplify

x = 4, x = - 2 + 23 i, x = - 2 - 23 i

18 x^{5} + 6 x^{4} - 24 x^{3} = 6 x^{2}

2 y^{4} + 3 y^{3} - 16 y^{2} + 15 y - 4 = 0

(u + 4)^{3} = - (u + 4)^{2}

R, V = \frac{4}{3} π R^{3}

x^{3} = \frac{8}{343}

What are the solutions to the equation 2x^3+72=200 ?
The solutions to the equation 2x^3+72=200 are x=4,x=-2+2sqrt(3)i,x=-2-2sqrt(3)i
Find the zeros of 2x^3+72=200
The zeros of 2x^3+72=200 are x=4,x=-2+2sqrt(3)i,x=-2-2sqrt(3)i