What are the solutions to the equation 0=x^3-3x^2+2x ?

The solutions to the equation 0=x^3-3x^2+2x are x=0,x=1,x=2

Find the zeros of 0=x^3-3x^2+2x

The zeros of 0=x^3-3x^2+2x are x=0,x=1,x=2

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0 = x^{3} - 3 x^{2} + 2 x

x = 0, x = 1, x = 2

Solution steps

0 = x^{3} - 3 x^{2} + 2 x

Switch sides

x^{3} - 3 x^{2} + 2 x = 0

Factor

x^{3} - 3 x^{2} + 2 x : x (x - 1) (x - 2)

x (x - 1) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 1 = 0 or x - 2 = 0

Solve

x - 1 = 0 : x = 1

Solve

x - 2 = 0 : x = 2

The solutions are

x = 0, x = 1, x = 2

x^{4} + 7 x^{2} - 18 = 0

7 x = x^{6} + 5 (3 x + 3) - x

x^{3} - 2 x = 1

R, T^{2} = R^{3}

(x - 1)^{4} + 2 (x - 1)^{2} - 3 = 0

What are the solutions to the equation 0=x^3-3x^2+2x ?
The solutions to the equation 0=x^3-3x^2+2x are x=0,x=1,x=2
Find the zeros of 0=x^3-3x^2+2x
The zeros of 0=x^3-3x^2+2x are x=0,x=1,x=2