What are the solutions to the equation (x^2+x-1)-x^3-3x=2 ?

The solutions to the equation (x^2+x-1)-x^3-3x=2 are x\approx-0.84373…

Find the zeros of (x^2+x-1)-x^3-3x=2

The zeros of (x^2+x-1)-x^3-3x=2 are x\approx-0.84373…

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(x^{2} + x - 1) - x^{3} - 3 x = 2

x \approx - 0.84373 \dots

Solution steps

(x^{2} + x - 1) - x^{3} - 3 x = 2

Refine

- x^{3} + x^{2} - 2 x - 1 = 2

Move

2

to the left side

- x^{3} + x^{2} - 2 x - 3 = 0

Find one solution for

- x^{3} + x^{2} - 2 x - 3 = 0

using Newton-Raphson:

x \approx - 0.84373 \dots

Apply long division:

\frac{- x ^{3} + x ^{2} - 2 x - 3}{x + 0.84373 \dots} = - x^{2} + 1.84373 \dots x - 3.55562 \dots

- x^{2} + 1.84373 \dots x - 3.55562 \dots \approx 0

Find one solution for

- x^{2} + 1.84373 \dots x - 3.55562 \dots = 0

using Newton-Raphson:

No Solution for

x \in R

The solution is

x \approx - 0.84373 \dots

x^{3} + 4 x^{2} + 8 x + 16 = 0

45 x^{3} - 15 x^{2} - 30 x = 0

x^{3} - 28 x + 48 = 0

r^{3} - 2 r^{2} + r = 0

y, x = 7 + (2 y + 1)^{3}

What are the solutions to the equation (x^2+x-1)-x^3-3x=2 ?
The solutions to the equation (x^2+x-1)-x^3-3x=2 are x\approx-0.84373…
Find the zeros of (x^2+x-1)-x^3-3x=2
The zeros of (x^2+x-1)-x^3-3x=2 are x\approx-0.84373…