What are the solutions to the equation 3x^2-x+8=0 ?

The solutions to the equation 3x^2-x+8=0 are x= 1/6+i(sqrt(95))/6 ,x= 1/6-i(sqrt(95))/6

Find the zeros of 3x^2-x+8=0

The zeros of 3x^2-x+8=0 are x= 1/6+i(sqrt(95))/6 ,x= 1/6-i(sqrt(95))/6

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3 x^{2} - x + 8 = 0

x = \frac{1}{6} + i \frac{95}{6}, x = \frac{1}{6} - i \frac{95}{6}

Solution steps

3 x^{2} - x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 3 \cdot 8}{2 \cdot 3}

Simplify

(- 1)^{2} - 4 \cdot 3 \cdot 8 : 95 i

x_{1, 2} = \frac{- ( - 1 ) \pm 95 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 95 i}{2 \cdot 3}, x_{2} = \frac{- ( - 1 ) - 95 i}{2 \cdot 3}

x = \frac{- ( - 1 ) + 95 i}{2 \cdot 3} : \frac{1}{6} + i \frac{95}{6}

x = \frac{- ( - 1 ) - 95 i}{2 \cdot 3} : \frac{1}{6} - i \frac{95}{6}

The solutions to the quadratic equation are:

x = \frac{1}{6} + i \frac{95}{6}, x = \frac{1}{6} - i \frac{95}{6}

4 = x 2

\frac{12 3}{8}

12 x^{3} - 23 x^{2} - 3 x + 2 = 0

∣ x + 2 ∣ > 5

9 x^{2} - 72 x + 144

What are the solutions to the equation 3x^2-x+8=0 ?
The solutions to the equation 3x^2-x+8=0 are x= 1/6+i(sqrt(95))/6 ,x= 1/6-i(sqrt(95))/6
Find the zeros of 3x^2-x+8=0
The zeros of 3x^2-x+8=0 are x= 1/6+i(sqrt(95))/6 ,x= 1/6-i(sqrt(95))/6