What are the solutions to the equation (y^2-y-30)(5y-40)=0 ?

The solutions to the equation (y^2-y-30)(5y-40)=0 are y=-5,y=6,y=8

Find the zeros of (y^2-y-30)(5y-40)=0

The zeros of (y^2-y-30)(5y-40)=0 are y=-5,y=6,y=8

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(y^{2} - y - 30) (5 y - 40) = 0

y = - 5, y = 6, y = 8

Solution steps

(y^{2} - y - 30) (5 y - 40) = 0

Factor

(y^{2} - y - 30) (5 y - 40) : 5 (y + 5) (y - 6) (y - 8)

5 (y + 5) (y - 6) (y - 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y + 5 = 0 or y - 6 = 0 or y - 8 = 0

Solve

y + 5 = 0 : y = - 5

Solve

y - 6 = 0 : y = 6

Solve

y - 8 = 0 : y = 8

The solutions are

y = - 5, y = 6, y = 8

x^{3} + x^{2} + 4 x - 4 = 0

144 x^{4} + 24 x^{2} + 1 = 0

77 = 16 \cdot (1 + r)^{4}

- 9 = t^{8} - 12

x^{3} - x^{2} - 11 x + 3 = 0

What are the solutions to the equation (y^2-y-30)(5y-40)=0 ?
The solutions to the equation (y^2-y-30)(5y-40)=0 are y=-5,y=6,y=8
Find the zeros of (y^2-y-30)(5y-40)=0
The zeros of (y^2-y-30)(5y-40)=0 are y=-5,y=6,y=8